Focal chord length of parabola
WebThe length of a focal chord of the parabola y 2=4ax at a distance b from the vertex is c. Then A 2a 2=bc B a 3=b 2c C ac=b 2 D b 2c=4a 3 Hard Solution Verified by Toppr Correct option is D) Equation of the focal line passing through (a,0) is y=m(x−a) The distance of this line from the vertex is b. ⇒b= ∣∣∣∣∣ 1+m 2am ∣∣∣∣∣ ⇒b 2(1+m 2)=a 2m 2 .... (1) WebFOCAL CHORD : A chord of the parabola, which passes through the focus is called a FOCAL CHORD. ... Also prove that CG = e2CN, where PN is the ordinate of P. x 2 y2 Q.16 Prove that the length of the focal chord of the ellipse 1 which is inclined to the major axis at a 2 b2 2ab 2 angle is . a 2 sin 2 b 2 cos2 ...
Focal chord length of parabola
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WebThe length of the intercept on the normal at the point (a t 2, 2 a t) of the parabola y 2 = 4 a x made by the circle which is described on the focal distance of the given point as diameter is. Hard. View solution > If the tangent and normals at the extremities of a focal chord of a parabola intersect at (x 1 ... WebThe focal chord is a line segment that connects the focus of the parabola to the vertex of the parabola. The length of the focal chord is equal to the distance between the focus …
WebThe length of a focal chord of the parabola y 2=4ax at a distance b from the vertex is c. Then. A a 2=bc B a 3=b 2c C b 2=ac D b 2c=4a 3 Medium Solution Verified by Toppr Correct option is D) Parabola P:y²=4ax−−(1) Vertex =O(0,0) Focus: F(a,0) Let the Focal chord L be (y−0)=m(x−a) So y=mx−ma−−(2)\ Given b = Distance of O from L. WebThe length of a focal chord of the parabola y2 =4ax at a distance ‘b’ from the vertex is ‘c’, then A 2a2=bc B a3=b2c C b2 =ac D b2c=4a3 Solution The correct option is D b2c =4a3 Let the angle made by focal chord with x – axis be θ ∴ sinθ= b a Length of focal chord, c =4acosec2θ ⇒ c= 4a(a b)2 ⇒ b2c =4a3 Suggest Corrections 28 Similar questions Q.
WebThe latus rectum of a parabola is the chord that is passing through the focus of the parabola and is perpendicular to the axis of the parabola. The latus rectum of parabola can also be understood as the focal chord which is parallel to the directrix of parabola.The length of latus rectum for a standard equation of a parabola y 2 = 4ax is equal to LL' = 4a. WebLength of the focal chords of the parabola y 2=4ax at a distance p from the vertex is A p2a 2 B p 2a 2 C p 24a 3 D ap 2 Hard Solution Verified by Toppr Correct option is C) y 2=4ax Slope of OP= Slope of OQ ⇒t 2= t 1−1 ∴ P(at 2,2at) & Q(t 2a, t−2a) Let length of focal chord be C. ∴ (at 2− t 2a)2+(2at+ t2a)2=C ⇒ a 2(t 2− t 21)2+(2a) 2(t+ t1)2=C
WebApr 6, 2024 · Substitute the value you get in the expression of length of focal chord ‘c’ and get the value of c. Complete step-by-step answer: We have been given the equation of parabola as ${{y}^{2}}=4ax$ . We need to find the focal chord of the parabola at a distance p from the vertex. Let us take 2 points on the parabola as P and Q.
WebAnswer: Consider the parabola: The distance between the vertex and the focus, measured along the axis of symmetry, is the "focal length". The "latus rectum" is the chord of the parabola which is parallel to the directrix and passes through the focus. In fact the “latus rectum” used to be calle... in wall bathroom cabinet mirrorWebThis is a parabola with vertex (2/9 , 8/9) Focal Chord of Parabola : Any chord to y 2 = 4ax which passes through the focus is called a focal chord of the parabola y 2 = 4ax. Let y 2 = 4ax be the equation of a parabola and (at 2, 2at) a point P on it. Suppose the coordinates of the other extremity Q of the focal chord through P are (at 1 2, 2at 1). in wall bathroom heaters lowe\u0027sWebDec 8, 2024 · Question 4 :$$ $$ Let PQ be a focal chord of a parabola with origin as a focus . Coordinates of point P and Q be (-2,0) and (4,0) respectively . Find length of latus rectum and equation of tangent at vertex of parabola. in wall bathroom doorWebSolution The correct option is A (8, –8) For the parabola y2 = 8x; focus S (2, 0). Given point is P (1 2,2) Slope of ←→ SP is 2−0 1 2−2 = −4 3 Equation to ←→ SP is4x+3y−8= 0 4x+3y−8= 0⇒ 4x=8−3y Substituting this value of 4x in y2 = 8x we get y2 = 2(8−3y) ⇒y2+6y−16−16 =0 ⇒(y+8)(y−2) = 0 ⇒ y= 2or−8 y =−8 ⇒4x =8−3(−8)= 32⇒ x= 8 ∴ point … in wall bathroom cabinetsWebMar 26, 2024 · Point of intersection in fourth quadrant gives me a ∈ [ 0, 1) So, parabola is y 2 = 4 ( a 2 − a + 1) x + 5 I know that length of focal chord is a ( t + 1 t) 2 for y 2 = 4 a x … in wall bathroom hampersWebPARABOLA ASSIGNMENT - Read online for free. Scribd is the world's largest social reading and publishing site. PARABOLA ASSIGNMENT. Uploaded by mynameis 1609. 0 ratings 0% found this document useful (0 votes) 0 views. 19 pages. Document Information click to expand document information. in wall bathroom heaterWebFocal length calculated from parameters of a chord Suppose a chord crosses a parabola perpendicular to its axis of symmetry. Let the length of the chord between the points where it intersects the parabola be c and … in wall bathroom fireplace